X^2+200x-3600=0

Solution for X^2+200x-3600=0 equation:

X^2+200X-3600=0

a = 1; b = 200; c = -3600;
Δ = b2-4ac
Δ = 2002-4·1·(-3600)
Δ = 54400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{54400}=\sqrt{1600*34}=\sqrt{1600}*\sqrt{34}=40\sqrt{34}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(200)-40\sqrt{34}}{2*1}=\frac{-200-40\sqrt{34}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(200)+40\sqrt{34}}{2*1}=\frac{-200+40\sqrt{34}}{2}
$